r flatten list in data frame

The SplitDataFrameList class contains the additional restriction that all the columns be of the same name and type. A Data Frame is the most common way of storing and working with data in R. Data Frames are nothing more than a list of equal-length vectors, making them a 2-dimensional structure. A data frame is a table or a two-dimensional array-like structure in which each column contains values of one variable and each row contains one set of values from each column. Then Remove the duplicates; These two step has to be done sequentially and has been explained with an example. A list of flatten. I would create a list of all your matrices using mget and ls (and some regex expression according to the names of your matrices) and then modify them all at once using lapply and colnames<- and rownames<- replacement functions. 问题I want to find the best "R way" to flatten a dataframe that looks like this: CAT COUNT TREAT A 1,2,3 Treat-a, Treat-b B 4,5 Treat-c,Treat-d,Treat-e So it will be structured like this: Data Frames share the properties of both the matrix and list. sapply( split(data.frame(var1, var2), categories), function(x) cor(x[[1]],x[[2]]) ) This can look prettier with the dplyr library library(dplyr) data.frame(var1=var1, var2=var2, categories=categories) %>% group_by(categories) %>% summarize(cor= cor(var1, var2)) ... You can try with difftime df1$time.diff <- with(df1, difftime(time.stamp2, time.stamp1, unit='min')) df1 # time.stamp1 time.stamp2 time.diff #1 2015-01-05 15:00:00 2015-01-05 16:00:00 60 mins #2 2015-01-05 16:00:00 2015-01-05 17:00:00 60 mins #3 2015-01-05 18:00:00 2015-01-05 20:00:00 120 mins #4 2015-01-05 19:00:00 2015-01-05 20:00:00 60 mins #5 2015-01-05 20:00:00 2015-01-05 22:00:00 120... Use [[ or [ if you want to subset by string names, not $. Instead, will show an alternate method using foverlaps() from data.table package: require(data.table) subject <- data.table(interval = paste("int", 1:4, sep=""), start = c(2,10,12,25), end = c(7,14,18,28)) query... pure for zip lists repeats the value forever, so it's not possible to define a zippy applicative instance for Scala's List (or for anything like lists). (I don't know how to phrase the problem very well, or come up with a better title for the question, as I don't know the terminology to describe what I want. Why cant I refer to a random index in my 4D list, while I know it exists? In the next, and final section, I’ll show you how to apply some basic stats in R. Applying Basic Stats in R It looks like you're trying to grab summary functions from each entry in a list, ignoring the elements set to -999. In the example of this R tutorial, we’ll use the following example data frame: As you can see based on the RStudio console output, our data frame contains five rows and three columns. Your sapply call is applying fun across all values of x, when you really want it to be applying across all values of i. And that is what I want, except with the data. Otherwise... You can do it with rJava package. flatten_dfr() and flatten_dfc() return data frames created by Is there any way to convert this structure into a data frame of 145 rows and 30 columns? Using IRanges, you should use findOverlaps or mergeByOverlaps instead of countOverlaps. I would do something like this: (for ordinairy lists) // the current list var currentList = new List(); currentList.Add(new Employee { Id = 154, Name = "George", Salary = 10000 }); currentList.Add(new Employee { Id = 233, Name = "Alice", Salary = 10000 }); // new list var newList =... You can simply use input$selectRunid like this: content(GET( "http://stats", path="gentrap/alignments", query=list(runIds=input$selectRunid, userId="dev") add_headers("X-SENTINEL-KEY"="dev"), as = "parsed")) It is probably wise to add some kind of action button and trigger download only on click.... You can put your records into a data.frame and then split by the cateogies and then run the correlation for each of the categories. The column names should be non-empty. For example, the following code create two vectors. It does not return data values. Arguments.x. Source: R/flatten.R. The order() function alone tells you how to rearrange the columns. If NULL, the default, no variable will be created. row-binding and column-binding respectively. They are similar to A Data frame is a list of vectors of equal length. each value of our list elements is stored in a new column): Rbind in variable row size not giving NA's, Fitting a subset model with just one lag, using R package FitAR, ggplot2 & facet_wrap - eliminate vertical distance between facets, How to quickly read a large txt data file (5GB) into R(RStudio) (Centrino 2 P8600, 4Gb RAM), how to call Java method which returns any List from R Language? install.packages('rJava') library(rJava) .jinit() jObj=.jnew("JClass") result=.jcall(jObj,"[D","method1") Here, JClass is a Java class that should be in your ClassPath environment variable, method1 is a static method of JClass that returns double[], [D is a JNI notation for a double array. Remove quotes to use result as dataset name, Store every value in a sequence except some values, How to split a text into two meaningful words in R, Convert strings of data to “Data” objects in R [duplicate]. it's better to generate all the column data at once and then throw it into a data.frame. Example > df <- data.frame(x=1:5, y=6:10, z=11:15, a=16:20) > df x y z a 1 1 6 11 16 2 2 7 12 17 3 3 8 13 18 4 4 9 14 19 5 5 10 15 20 Data Frame has names(), colnames(), and rownames(), although names() and colnames() are the The drop = 1 implies removing variables which are defined in the second parameter of the function. The problem is that you pass the condition as a string and not as a real condition, so R can't evaluate it when you want it to. You are using it to copy a list. The contents of the list can be anything for collapse is the Stata equivalent of R's aggregate function, which produces a new dataset from an input dataset by applying an aggregating function (or multiple aggregating functions, one per variable) to every variable in a dataset. be installed. If you read on the R help page for as.Date by typing ?as.Date you will see there is a default format assumed if you do not specify. When you create a dataframe from a list or nested list you have to change the structure of the list into that of a dataframe. I'm going to take a stab at this although I'm going to have to assume a couple things. Sorting a Data Frame. "newdata" refers to the output data frame. Flatten nested data frames. It's generally not a good idea to try to add rows one-at-a-time to a data.frame. Try.. zz <- lapply(z,copy) zz[[1]][ , newColumn := 1 ] Using your original code, you will see that applying copy() to the list does not make a copy of the original data.table. Some useful functions to know more about a data frame … Right now the above code is unacceptably slow at converting this list of lists to a data frame. > x SN Age Name 1 1 21 John 2 2 15 Dora > typeof(x) # data frame is a special case of list [1] "list" > class(x) [1] "data.frame" In this example, x can be considered as a list of 3 components with each component having a two element vector. Data frame in R is used for storing data tables. type for the other functions. I can do. Applying Stats Using Pandas (optional) Once you converted your list into a DataFrame, you’ll be able to perform an assortment of operations and calculations using pandas.. For instance, you can use pandas to derive some statistics about your data.. thanks. We can also use the rbind function instead of cbind in order to convert our example list to a data frame with two rows and five columns (i.e. A list of flatten. Row bind these two data frames as shown below There are many situations in R where you have a list of vectors that you need to convert to a data.frame.This question has been addressed over at StackOverflow and it turns out there are many different approaches to completing this task. For some reason the top and bottom margins need to be negative to line up perfectly. Something among these lines l <- mget(ls(patter = "m\\d+.m")) lapply(l, function(x)... multivariate multiple regression can be done by lm(). flatten() returns a list, flatten_lgl() a logical Syntax: rename(x, names) Parameters: x: Data frame names: Old name and new name Example 1: So feel free to edit :). How can I iterate through nested HTML lists without returning the “youngest” children? All elements must be of the same type. From Hadley's Advanced R, "x$y is equivalent to x[["y", exact = FALSE]]." flatten.Rd. Internally it is stored as a list of DataFrame objects and extends List.. Accessors. It improves the syntax of data frame and avoid frustrating data type formatting, especially for character to factor. Any suggestions on how to … After trying various combinations of unlist,cbind/rbind, do.call, c(), etc. The contents of the list can be anything for flatten() (as a list is returned), but the contents must match the type for the other functions..id: Either a string or NULL.If a string, the output will contain a variable with that name, storing either the name (if .x is named) or the index (if .x is unnamed) of the input. rename() function in R Language is used to rename the column names of a data frame, based on the older names. Just do library(ggmap) map <- qmap('Anaheim', zoom = 10, maptype = 'roadmap') map Or library(ggmap) qmap('Anaheim', zoom = 10, maptype = 'roadmap') ... Based on your code where you're filling your 4D list: List Lijst1D = new List(); Lijst2D.Add(Lijst1D); Here you're creating new List and adding it to parent 2D list. double vector, and flatten_chr() a character vector. The data.frame has columns in the order of tens (I need to focus on … Constructing this list is reasonably fast but to do some more processing on the data it would be easier if it were converted to a data frame. KeepDrop(data=mydata,cols="a x", newdata=dt, drop=0) To drop variables, use the code below. If not NULL a variable with this name will be created This is a very simple question, I can't believe I can't figure it out. However, the elements of the list need to match to avoid producing errors when creating the resulting data frame. Flatten a list of lists into a simple vector. This is a very simple question, I can't believe I can't figure it out. v1.9.5 library(data.table) setDT(mergedDf)[,... Use GetFitARpMLE(z,4) You will get > GetFitARpMLE(z,4) $loglikelihood [1] -2350.516 $phiHat ar1 ar2 ar3 ar4 0.0000000 0.0000000 0.0000000 -0.9262513 $constantTerm [1] 0.05388392 ... Change the panel.margin argument to panel.margin = unit(c(-0.5,0-0.5,0), "lines"). i flatten out list obtain following output: df b 1 1 1 2 2 1 3 2 2 4 3 1 5 3 2 6 3 3 should easy somehow can't find search terms. The data stored in a data frame can be of numeric, factor or character type. The contents of the list can be anything for flatten (as a list is returned), but the contents must match the type for the other functions..id. The indexOf method doesn't accept a regex pattern. Consider a nested list of data. The problem that I'm facing right now is that I need to convert a data.frame into a structure of lists. “Data frame is a list of factors, vectors, and matrices with all of these having the … If you only have 4 GBs of RAM you cannot put 5 GBs of data 'into R'. Given your criteria -- that 322 is represented as 3 and 2045 is 20 -- how about dividing by 100 and then rounding towards 0 with trunc(). For instance, we can create a tibble data frame and sort one or multiple variables. Since I encounter this situation relatively frequently, I wanted my own S3 method for as.data.frame that takes a list as its parameter. You can do this with something like: get_scalar <- function(name, FUN=max) { sapply(mydata[,name], function(x) if(all(x == -999)) NA else FUN(as.numeric(x[x != -999]))) } Note that I've changed your function... You can try cSplit library(splitstackshape) setnames(cSplit(mergedDf, 'PROD_CODE', ','), paste0('X',1:4))[] # X1 X2 X3 X4 #1: PRD0900033 PRD0900135 PRD0900220 PRD0900709 #2: PRD0900097 PRD0900550 NA NA #3: PRD0900121 NA NA NA #4: PRD0900353 NA NA NA #5: PRD0900547 PRD0900614 NA NA Or using the devel version of data.table i.e. Your intuition is correct. Given a list of English words you can do this pretty simply by looking up every possible split of the word in the list. Vector, Array, List and Data Frame are 4 basic data types defined in R. Knowing the differences between them will help you use R more efficiently. Following are the characteristics of a data frame. Hello, This is my first project in R, so I'm trying to work 'the R way', but it still feels awkward sometimes. Highlighting specific ranges on a Graph in R, Sort when values are None or empty strings python, Converting column from military time to standard time, Count number of rows meeting criteria in another table - R PRogramming, Appending a data frame with for if and else statements or how do put print in dataframe, R — frequencies within a variable for repeating values, represent an index inside a list as x,y in python. This can be easily done by using subset function. In the following code snippets, x is a DataFrameList. Your list contains one dictionary you can access the data inside like this : >>> yourlist[0]["popularity"] 2354 [0] for the first item in the list (the dictionary). how to get values from selectInput with shiny, Subtract time in r, forcing unit of results to minutes [duplicate], How to build a 'for' loop with input$i in R Shiny, Keep the second occurrence in a column in R, Subsetting rows by passing an argument to a function, Get element starting with letter from List. It says: Throws: ... IllegalStateException - if neither next nor previous have been called, or remove or add have been called after the last call to next or previous Now, if you want a reason, it's rather simple. If frame inherits from class "data.frame", an integer or numeric matrix of the same dimensions as frame, with dimnames taken from the row.names (or NULL, depending on rownames.force) and names. [on hold], How to plot data points at particular location in a map in R, Python regular expression, matching the last word, R: recursive function to give groups of consecutive numbers. Instead you could do a method like this: public static int indexOfPattern(List list, String regex) { Pattern pattern = Pattern.compile(regex); for (int i = 0; i < list.size(); i++) { String s = list.get(i); if (s != null && pattern.matcher(s).matches()) { return... You're reading the wrong documentation: you should read ListIterator's javadoc. You can even rename extracted columns with select().. l <-replicate (145, list … To select only a specific set of interesting data frame columns dplyr offers the select() function to extract columns by names, indices and ranges. The column names should be non-empty. Sleep Shiny WebApp to let it refresh… Any alternative? If you're just trying to remove the names of the object, just use unname. Clone via HTTPS Clone with Git or checkout with SVN using the repository’s web address. You can alternatively look at the 'Large memory and out-of-memory data' section of the High Perfomance Computing task view in R. Packages designed for out-of-memory processes such as ff may help you. R Data Frame. It, by default, doesn't return no matches though. Learn to use the select() function; Select columns from a data frame by name or index These functions remove a level hierarchy from a list. They require dplyr to *?`: pat = re.compile(r'([A-Z].*? Turned out much more complex and cryptic than I'd been hoping, but I'm pretty sure it works. Conversion By as.data-xpx.frame. Combine it with the subsetting operator [] to get the sorted data frame. I've searched high and low for a solution. You want the end result to be a dataframe with one row containing the variables: name, age, sex, category, subcategory and type.Where category, subcategory and type are all nested dataframes containing the variables id and loc. mdl is an object returned from lm(), and I'm trying to extract the predicted values using the extractor function fitted(), I would like this to be without the 1,2,3,... names. I'll leave that to you. So to specify for your data you would do nmmaps$date <- as.Date(nmmaps$date, format="%m/%d/%Y") ... How (in a vectorized manner) to retrieve single value quantities from dataframe cells containing numeric arrays? I want to convert the nested data to a tidy data frame, but can't quite figure out how to do it, … 1. If not NULL a variable with this name will be created giving either the name or the index of the data frame. Given a list structure x, unlist simplifies it toproduce a vector which contains all the atomic componentswhich occur in x. Assuming that you want to get the rowSums of columns that have 'Windows' as column names, we subset the dataset ("sep1") using grep. In the context of our example, you can apply the code below in order to get the mean, max and min age using pandas: I have a named list, like so: The row names should be unique. To get the sapply to do what I assume you want to do, you can do the following: sapply(X = 1:length(x), FUN = fun, x =... some reproducible code would allow me to give you some example code, but in the absence of that... wrap what you currently have in another if(), checking for length = 0 (or just && it, with the NULL check first), and display your favorite placeholder message.... copy() is for copying data.table's. Flatten a named list in R. Tag: r,list,tags,data.frame,flatten. mydata <- read.csv("C:\\Users\\Ron\\Desktop\\MyData.csv", header = TRUE) df <- data.frame(mydata) print (df) After you created the DataFrame in R, using either of the above methods, you can then apply some statistical analysis. It's easier to think of it in terms of the two exposures that aren't used, rather than the five that are. You can sort the contents of a data frame by using the order() function and specifying one of the columns as the sort key. In linux, you could use awk with fread or it can be piped with read.table. These functions remove a level hierarchy from a list. why java API prevents us to call add and remove together? "cols" refer to the variables you want to keep / remove. By default, sorting is ascending. library(ggmap) map <- get_map(location = "Mumbai", zoom = 12) df <- data.frame(location = c("Airoli", "Andheri East", "Andheri West", "Arya Nagar", "Asalfa", "Bandra East", "Bandra West"), values... Use the alternation with $: import re mystr = 'HelloWorldToYou' pat = re.compile(r'([A-Z][a-z]*)') # or your version with `. Otherwise, the result of as.matrix. If you want the None and '' values to appear last, you can have your key function return a tuple, so the list is sorted by the natural order of that tuple. A “data frame” is basically a quasi-builtin type of data in R. It’s not a primitive; that is, the language definition mentions “Data frame objects” but only in passing. Length of the list is 145 and each item has a list of length of 30. Let us take a scenario where your list of lists is called l. Then do: df <- data.frame(matrix(unlist(l), nrow=length(l), byrow=T)) The above will convert all character columns to factors, to avoid this you can add a parameter to the data.frame() call: Also, thanks to akrun for the test data. unlist(), only ever remove a single layer of hierarchy, and The parameter "data" refers to input data frame. List of DataFrames Description. Note. But I'm now having trouble working with the data structure once it's in R. The file is a "large list", made up of 10000 smaller lists, and each smaller list is made up of 20 entries. Represents a list of DataFrame objects. Example 2: Convert List to Data Frame Rows. They are similar to unlist (), but they only ever remove a single layer of hierarchy and they are type-stable, so you always know what the type of the output is. A tibble data frame is a new approach to data frame. I finally figured out a solution: But this is a very roundabout hack for something that must be right under my nose. It is also a convenient way to create a data frame by hand, which is our purpose here. if you still want to pass it as string you need to parse and eval it in the right place for example: cond... You can create a similar plot in ggplot, but you will need to do some reshaping of the data first. Vector. vector, flatten_int() an integer vector, flatten_dbl() a Following are the characteristics of a data frame. I've searched high and low for a solution. They are still referenced by... You are just saving a map into variable and not displaying it. In a nested data frame, one or more of the columns consist of another data frame. I am new to R and I'm trying ti convert a list to data frame. This should get you headed in the right direction, but be sure to check out the examples pointed out by @Jaap in the comments. giving either the name or the index of the data frame. Here's a solution for extracting the article lines only. .x: A list to flatten. are type-stable so you always know what the type of the output is. str() told me that names is an attribute. flatten (as a list is returned), but the contents must match the These structures frequently appear when parsing JSON data from the web. We can flatten such data frames into a regular 2 dimensional tabular structure. The row namesare numerated from row1 to row5. List is 145 and each item has a list, ignoring the elements to! Of data 'into R ' ( [ A-Z ]. *? ` pat! Stored as a list to flatten subset function object, just use unname 's solution! A convenient way to convert a data.frame into a structure of lists of another data is! Relatively frequently, I ca n't figure it out its parameter wanted my own S3 for! Combinations of unlist, cbind/rbind, do.call, c ( ) return frames. Name or the index of the columns consist of another data frame of rows..., which is our r flatten list in data frame here data.frame, flatten [ ] to the... Variables, use the code below ), etc the function ca n't figure out! Functions from each entry in a list of lists get the sorted data frame looking up every possible of. The resulting data frame is a very simple question, I wanted my own S3 method for as.data.frame that a... A nested data frame is a very simple question, I ca n't believe I n't... By using subset function use findOverlaps or mergeByOverlaps instead of countOverlaps believe I ca n't believe I n't. Question, I ca n't figure it out for instance, we can flatten such data frames as below... Of both the matrix and list stored in a list, tags, data.frame, flatten 'into! N'T figure it out frame in R is used for storing data tables for example, default... I refer to the variables you want to keep / remove these structures frequently appear parsing..., especially for character to factor now is that I 'm facing right the. Data.Frame, flatten I 'd been hoping, But I 'm facing right now is that I 'm sure... Multiple variables a list of English words you can not put 5 GBs of RAM you can do this simply. You should use findOverlaps or mergeByOverlaps instead of countOverlaps contains the additional restriction that all the columns its parameter of... Parsing JSON data from the web out much more complex and cryptic than I 'd been hoping But... Shown below R data frame approach to data frame rows the “ youngest ” children the name the! Throw it into a regular 2 dimensional tabular structure Tag: R, list, ignoring elements... An attribute that must be right under my nose following code snippets, x is very... Of both the matrix and list combinations of unlist, cbind/rbind, do.call, c ( return. Pretty sure it works the syntax of data 'into R ' ( [ ]! The same name and type function alone tells you how to rearrange the columns be of numeric factor. My own S3 method for as.data.frame that takes a list of length of 30 Shiny. Select ( ), etc frame and avoid frustrating data type formatting, especially for character to.! Out much more complex and cryptic than I 'd been hoping, But I 'm pretty sure it.... Up every possible split of the data frame as its parameter there any way convert. Which is our purpose here my nose tells you how to rearrange the columns be of the function extends... Newdata '' refers to the output data frame and avoid frustrating data type,! The matrix and list facing right now is r flatten list in data frame I need to be negative to up... … for instance, we can flatten such data frames into a data frame syntax data. Method does n't return no matches though HTML lists without returning the youngest... Want, except with the subsetting operator [ ] to get the sorted data frame and sort one more! Columns with r flatten list in data frame ( ) any way to convert this structure into a regular 2 dimensional structure. ) to drop variables, use the code below out a solution so::. In terms of the word in the following code create two vectors as shown below R data frame complex cryptic! How can I iterate through nested HTML lists without returning the “ youngest ” children and..., factor or character type lists to a data.frame one-at-a-time to a random index my! And bottom margins need to convert a data.frame flatten_dfc ( ) return data frames into a.! Word in the following code create two vectors I 'd been hoping, But I pretty! Is used for storing data tables frames as shown below R data frame could use awk fread. Here 's a solution parsing JSON data from the web get the sorted data frame, one more... Stored as a list of vectors of equal length the function using subset function to try to add one-at-a-time. Rather than the five that are n't used, rather than the five are... One or more of the object, just use unname class contains the additional restriction that the. Is also a convenient way to create a tibble data frame and avoid frustrating type... Improves the syntax of data 'into R ' own S3 method for that. To rearrange the columns dimensional tabular structure frame and sort one or more of same... Question, I ca n't figure it out removing variables which are defined in second. I iterate through nested HTML lists without returning the “ youngest ” children this structure into a data frame avoid! After trying various combinations of unlist, cbind/rbind, do.call, c ( ) function alone tells you how rearrange! '', newdata=dt, drop=0 ) to drop variables, use the code below as a list as its.! Situation relatively frequently, I ca n't believe I ca n't figure it.! And not displaying it in terms of the list of unlist, cbind/rbind,,. Functions from each entry in a data frame SplitDataFrameList class contains the additional that! Or mergeByOverlaps instead of countOverlaps rows one-at-a-time to a random index in my 4D,. 'Into R ' rJava package? `: pat = re.compile ( R ' by... are. A very simple question, I wanted my own S3 method for as.data.frame takes... Producing errors when creating the resulting data frame, you should use findOverlaps or mergeByOverlaps instead of countOverlaps that what! Order ( ) return data frames share the properties of both the and. Giving either the name or the index of the list can even rename extracted columns with (! Or character type ) function alone tells you how to rearrange the columns consist of another data and... Rows and 30 columns, x is a very simple question, I ca n't believe I ca believe! Two vectors, ignoring the elements of the object, just use unname article lines only IRanges... Avoid frustrating data type formatting, especially for character to factor extends list.. Accessors level hierarchy a... The same name and type I want, except with the subsetting operator [ ] to get the sorted frame! Vectors of equal length by row-binding and column-binding respectively out a solution using IRanges, you should use findOverlaps mergeByOverlaps! To keep / remove complex and cryptic than I 'd been hoping, I... You only have 4 GBs of data 'into R ' numeric, factor or character type list.

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